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Calculate ∆G°and log kc for 2cr+3fe^3+--------->2cr^3+. …

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Calculate ∆G°and log kc for 2cr+3fe^3+--------->2cr^3+. + 3fe E°celk=0.3v

    • Posted by Rajat Bisht 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Harshdeep Kaur 6 years, 7 months ago

    ∆G°=-nFE°cell=-6×96500×0.3= -173700J ∆G°=2.303RT log Kc= 2.303 ×0.0821×298 log Kc -173700/2.303×0.0821×298= log Kc Log Kc=3082.8 Kc= antilog (3082.8) Kc= antilog(3.082×10^3) Kc= 1.205×10^5

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