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If the common difference of an A.P is, find a6_a12

Posted by Shailendra Singh 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

Let the first term of an A.P be {tex} a{/tex}, common difference {tex}d{/tex},
{tex}d = - 6{/tex}
a_n = a + (n -1)d
a₁₆ = a + (16 - 1)(- 6)
= a + (15)(- 6)
= a - 90
a₁₂ = a + (12 - 1)(-6 )
= a + 11(-6)
= a - 66
a₁₆ -a₁₂ = (a- 90) - ( a - 66)
= a - 90 - a + 66
= - 24

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