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tan square theta minus sin square …

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tan square theta minus sin square theta

Posted by Sailesh Mohanty 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

tan²θ– sin²θ
{tex} = {\tan ^2}\theta - \frac{{{{\sin }^2}\theta }}{{{{\cos }^2}\theta }} \cdot {\cos ^2}\theta \left[ {\because {{\tan }^2}\theta = \frac{{{{\sin }^2}\theta }}{{{{\cos }^2}\theta }}} \right]{/tex}
= tan²θ– tan²θcos²θ
= tan²θ(1 – cos²θ) {tex}\left[ \because \sin ^ { 2 } \theta = 1 - \cos ^ { 2 } \theta \right]{/tex}

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