Draw the graph of the following …
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Sia ? 6 years, 7 months ago
{tex}2x - 3y + 6 = 0{/tex}
{tex}\Rightarrow y = \frac { 2 x + 6 } { 3 }{/tex}
{tex}2x + 3y - 18 = 0{/tex}
{tex}\Rightarrow y = \frac { 18 - 2x } { 3 }{/tex}
Thus, the two graph lines intersect at (3, 4)
{tex}\therefore{/tex} x = 3 and y = 4 is the solution of given system of equations
The vertices of the triangle formed by these lines and y - axis are (3, 4), (0, 6) and (0, 2)
So, height of the triangle
= distance from (3, 4) to y-axis
= 3 units
Base = 4 units
Area of the triangle = {tex}\frac { 1 } { 2 } \times \text { base } \times \text{height}{/tex}
{tex}= \frac { 1 } { 2 } \times 4 \times 3{/tex}
= 6 sq. units
0Thank You