abx2+(b2-ac)x-bc=0 yeh jo 2 hai vo …

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Sia ? 6 years, 4 months ago
{tex}abx^2 + (b^2 - ac)x - bc = 0 {/tex}
{tex}\Rightarrow{/tex} {tex}abx^2 + b^2x - c(ax + b) = 0 {/tex}
{tex}\Rightarrow{/tex} {tex}bx(ax + b) - c(ax + b) = 0 {/tex}
{tex}\Rightarrow{/tex}{tex}(bx - c)(ax + b) = 0 {/tex}
x = {tex}\frac{c} {b}{/tex}, {tex}\frac{-b}{a}{/tex}
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