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The magnitude of entered and exerted …

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The magnitude of entered and exerted electric flux from a close surface are 4 *10^12 and 8*10^12 respectively.calculate the charge enclosed by this surface.

    • Posted by Unnati Vania 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Charu Chaturvedi 6 years, 4 months ago

    Since the net flux enclosed is equal to the one that left subtracted from the one that entered. So, ∆phi= 4*10^12-8*10^12 = -4*10^12 Nm^2/C Now according to Gauss Theorem, ∆phi= sigma q/epsilon zero i.e. Net electric flux = total charge/ permittivity of vacuum So, total charge = Net Electric Flux*Permittivity of vacuum Or sigma q= -4*10^12*8.85*10^-12 = -35.4 C

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