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Sin20.Sin40.sin60.sin80=3/16 (prove that )

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Sin20.Sin40.sin60.sin80=3/16 (prove that )
  • 1 answers

Gaurav Seth 6 years, 7 months ago

sin20. sin 40. sin60. sin80 

=> sin60[sin20.sin40.sin80] 

=>√3/2[sin20.sin(60-20).sin(60+20)] 

=>√3/2[sin 3(20)/4] 

=>√3/2[sin 60/4] 

=>√3/2[√3/2*4] 

=>√3/2*√3/8 

=3/16 

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