Sin20.Sin40.sin60.sin80=3/16 (prove that )
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Posted by Amarjit Kumar 6 years, 7 months ago
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Gaurav Seth 6 years, 7 months ago
sin20. sin 40. sin60. sin80
=> sin60[sin20.sin40.sin80]
=>√3/2[sin20.sin(60-20).sin(60+20)]
=>√3/2[sin 3(20)/4]
=>√3/2[sin 60/4]
=>√3/2[√3/2*4]
=>√3/2*√3/8
=3/16
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