(X+1)\2 + (y-1)\3= 8 (X-1)/3 + …
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Sia ? 6 years, 7 months ago
{tex}\frac { x + 1 } { 2 } + \frac { y - 1 } { 3 } = 9{/tex}
or, 3(x + 1) + 2(y -1) = 54
or, 3x + 3 + 2 y - 2 = 54
or, 3x + 2y +1 = 54
or, 3x + 2y = 53..........(i)
and {tex}\frac { x - 1 } { 3 } + \frac { y + 1 } { 2 } = 8{/tex}
or, 2(x -1 ) + 3 (y + 1) = 48
or, 2x - 2 + 3y + 3 = 48
or, 2x + 3y +1 = 48
or, 2x +3y = 47........(ii)
Multiply eqn.(i) by 3, multiply eqn.(ii) by 2 and subtracting both eqn
{tex}\therefore {/tex} {tex}x = \frac { 65 } { 5 } = 13{/tex}
Substitute the value of x in eqn. (ii),
2(13) + 3y = 47
or, 26 + 3y = 47
3y = 47-26 = 21
{tex}\therefore {/tex} {tex}y = \frac { 21 } { 3 } = 7{/tex}
Hence x = 13, y = 7.
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