In a triangle ABC right angled …

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Ram Kushwah 6 years, 8 months ago
{tex}\angle A=90{/tex}
{tex}\begin{array}{l}\sin B\cos C+\cos B\sin C=\sin(B+C)\\=\sin(180-A)\\=\sin A\\=\sin90=1\\\end{array}{/tex}
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