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(Xa\X-b) a2-ab+b2 x (Xb\X-c)b2-bc+c2 x (Xc\X-a) …

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(Xa\X-b) a2-ab+b2 x (Xb\X-c)b2-bc+c2 x (Xc\X-a) c2-ca+a2 =1

    • Posted by Aradhay Agarwal 6 years, 7 months ago

    CBSE > Class 09 > Mathematics
    • 5 answers

    Nisha Chaudhary 4 years, 8 months ago

    sirr

    10Thank You

    Nisha Chaudhary 4 years, 8 months ago

    sir send me solutions

    1Thank You

    Nisha Chaudhary 4 years, 8 months ago

    sir please please please please please please please

    1Thank You

    Nisha Chaudhary 4 years, 8 months ago

    please solve the answer

    4Thank You

    Nisha Chaudhary 4 years, 8 months ago

    (xa/xb)^a2-ab+b2 * (xb/xc)b2-bc+c2 * (xc/xa)c2-ac+a2

    4Thank You

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