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Show that for any set A …

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Show that for any set A and B, A=(A intersection B) union (A-B) and A union (B-A) = (A union B)
  • 1 answers

Ranjeet Kumar 6 years, 7 months ago

We have (A intersection B)union(A intersection B') ,since( A -- B)=A intersection B'. ==>A intersection (B union B'), by distributive law . ==>A intersection U ,as B union B'=U(union set). ==>A. Also,we have A union (B -- A) ==>A union (B intersection A') ==>(A union B ) intersection (A union A') ==>(A union B) intersection U ,since A union A'=U ==>A union B
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