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Posted by Jensi. C Jensi 8 years, 5 months ago
- 1 answers
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Amar Kumar 8 years, 5 months ago
{tex}\eqalign{ & {\left( {x - {1 \over x}} \right)^2} = {x^2} + {1 \over {{x^2}}} - 2x{1 \over x} \cr & \left( {x - {1 \over x}} \right) = \sqrt {18 - 2} \cr & \left( {x - {1 \over x}} \right) = 4 \cr & {x^3} - {1 \over {{x^3}}} = \left( {x - {1 \over x}} \right)\left( {{x^2} + 1 + {1 \over {{x^2}}}} \right) \cr} {/tex}
=4(18+1)
=76
1Thank You