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If A, B, C are any …

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If A, B, C are any 3angles then find the value of sin[B+C]/cos A.cos B+sin[C-A]/Cos C.Cos A+Sin[A-B]/Cos A. cos B

Posted by Raghavendra B N 6 years, 8 months ago

CBSE > Class 11 > Mathematics

1 answers

Ranjeet Kumar 6 years, 8 months ago

We have (sinB cosC + cosB sinC)/cosA cosB +(sinC cosA -- cosC sinA)/cosC cosA+(sinA cosB -- cosA sinB)/cosA cosB ==>(sinB cos^2 C +sinC cosB cosC +sinC cosA cosB -- sinA cosB cosC +sinA cosB cosC -- sinB cosA cosC)/cosA cosB cosC ==>{sinB cos^2C + sinC cosB(cosA + + cosC) -- sinB cosC cosA}/cosA cosB cosC ==>{ sinBcosC (cosC -- cosA)+ sinC cosB (cosA + cosC )}/ cosA cosB cosC YOU MUST CHECK YOUR QUESTION, IF IT IS CORRECT OR NOT. ALSO YOU CAN VERIFY THIS SOLUTION .

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