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the 4th term of an AP …

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the 4th term of an AP is zero prove that the 25th term of the AP is 3 times its 11th term
  • 1 answers

Sia ? 6 years, 7 months ago

We have,
a4 = 0
{tex}a + 3d = 0{/tex}
{tex}3d = -a{/tex}
or {tex}-3d = a{/tex}..........(i)
Now,
a25 = {tex}a + 24d{/tex}
= {tex}-3d + 24d{/tex} [Putting value of a from eq(i)]
= {tex}21d{/tex}...........(ii)
a11 = {tex}a + 10d{/tex}
= {tex}-3d + 10d{/tex}
= {tex}7d{/tex}.........(iii)
From eq(ii) and (iii), we get
a25 = 21 d
a25 = 3(7d)
a25 = 3a11
Hence Proved

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