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find the 31st term of an …

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find the 31st term of an AP whose 11th term is 38 and 16th term is 73
  • 1 answers

Sia ? 6 years, 4 months ago

Here a11 =38 and a16 =73
Using formula a n =a +(n−1)d, to find nth term of arithmetic progression,
38=a +(11−1) (d) And 73=a +(16−1)(d)
⇒ 38=a +10d And 73=a +15d
These are equations consisting of two variables.
We have, 38=a +10d ⇒ a =38−10d
Let us put value of a in equation (73=a +15d),
73=38−10d +15d ⇒ 35=5d
Therefore, Common difference =d =7
Putting value of d in equation 38=a +10d ,
38=a +70 ⇒ a =−32
Therefore, common difference = d = 7 and First term = a = -32
Using formula a n =a +(n−1)d , to find nth term of arithmetic progression,
a31=-32+(31−1)(7) =−32+210=178
Therefore, 31st term of AP is 178.

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