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Ap=8,3,-2.........find Sn

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Ap=8,3,-2.........find Sn

    • Posted by Om Kore 6 years, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 7 months ago

    Here {tex}a = 8,\ d = 3 - 8 = -5.{/tex}
    So, Sn = {tex}\frac{n}{2}{/tex}[2a + (n - 1)d]
    {tex}\Rightarrow{/tex} {tex}S_{n} = \frac n2(16 - 5n + 15) = \frac n2(31 - 5n){/tex}

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