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The 17th of an ap exceed …

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The 17th of an ap exceed it 10th by 7 .find the common difference.

Posted by Vijay Thakur 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

Let the first term and the common difference of the AP be a and d respectively.
Given that, a₁₇ = a₁₀+7
{tex} \Rightarrow {/tex} a + (17 - 1) d = a + (10 - 1)d + 7 {tex}\because {/tex}a_n = a +(n - 1)d
{tex} \Rightarrow {/tex} a + 16d = a + 9d + 7
{tex} \Rightarrow {/tex} 16d - 9d = 7
{tex} \Rightarrow {/tex} 7d = 7
{tex} \Rightarrow d = \frac{7}{7} = 1{/tex}
Hence, the common difference is 1.

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