The radius of two circle are …
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Sia ? 6 years, 4 months ago
Radius (r1) of 1st circle= 19 cm
Radius (r2) or 2nd circle = 9 cm
Let radius of 3rd circle be r
Circumference of 1st circle {tex}= 2\pi {r_1} = 2\pi \left( {19} \right) = 38\pi {/tex}
Circumference of 2nd circle {tex}= 2\pi {r_2} = 2\pi \left( 9 \right) = 18\pi {/tex}
Circumference of 3rd circle {tex} = 2\pi r{/tex}
Given that
Circumference of 3rd circle = circumference of 1st circle + circumference of 2nd circle
{tex}2\pi r = 38\pi + 18\pi = 56\pi {/tex}
{tex}r = \frac{{56\pi }}{{2\pi }} = 28{/tex}
So, radius of circle which has circumference equal to the sum of the circumference of given two circles is 28 cm.
Area of circle {tex} = \pi {r^2} = \left( {\frac{{22}}{7}} \right) \times 28 \times 28 = 2464c{m^2}{/tex}
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