P(x)=ax^2 + bx + c. If …

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Sia ? 6 years, 7 months ago
It is given that a + b + c = 0
We have function p(x) = ax2 + bx + c
Using remainder theorem by putting x=1 we get
p(1) = a {tex}\times{/tex} 12+ b + c
= a + b +c = 0 (given)
{tex}\therefore{/tex} x = 1 is one zero
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