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4u^2+8u

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4u^2+8u
  • 1 answers

Pravjyot Singh 6 years, 8 months ago

4usquare + 8u =4u(u+2) U=0 and also u =-2 So the zeroes are o and -2 Case 1... (a+b)=0+(-2) = -(-8)/4 =(-b/a) -2 = 8/4 Case 2... (a*b) = (0)(-2) = 0/4= (c/a) 0=0/4 Hence verified... Hope sooo ...it would help u..?
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