Determine graphically the vertices of a …
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Sia ? 6 years ago
x = 0, y = 0, y = 4 and 2x + y = 6
Graph of the equation y = 4:
{tex}2x + y = 6{/tex}:
We have {tex}2x + y = 6{/tex}
When y = 0, we get x = 3 and x = 0 gives y = 6.
Thus, we obtain the following table giving coordinates of two points on the line represented by the equation {tex}2x + y = 6{/tex}.
The coordinates of its vertices are {tex}O (0,0), C (3,0), E (1,4)\ and\ B (0,4).{/tex}
Area of trapezium {tex}\operatorname { OCEB } = \frac { 1 } { 2 } ( O C + B E ) \times O B = \frac { 1 } { 2 } ( 3 + 1 ) \times 4 = 8 \mathrm { sq } . units{/tex}
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