2 years ago salim was thrise …

Let Salim's present age be x years and his daughter's age be y years.
Two years ago,
Salim's age = (x - 2) years
Daughter's age = (y - 2) years
As per given condition
Two years ago, Salim was thrice as old as his daughter .
 x - 2 = 3(y - 2)
x - 2 = 3y - 6
{tex}\Rightarrow{/tex} x - 3y = -4 .........(i)
Six years hence,
Salim's age = (x + 6) years
Daughter's age = (y + 6) years
As per second condition
Six years later, he will be four years older than twice her age.
x + 6 = 2(y + 6) + 4
x + 6 = 2y + 12 + 4
{tex}\Rightarrow{/tex} x - 2y = 10 ...........(ii)
Subtracting (i) from (ii), we have
x - 2y - x  + 3y =10 - ( -4)
y = 14
Put y = 14 in (i)
{tex}\Rightarrow{/tex} x - 3(14) = -4
{tex}\Rightarrow{/tex}  x - 42 = - 4
{tex}\Rightarrow{/tex} x = 38
Therefore, the present age of Salim is 38 years and that of his daughter is 14 years.