Sum of 2 dogit number and …

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Gaurav Seth 6 years, 8 months ago
Let no at ones= x
Let no. at tens=10(x+3)
=10x+ 30
New no.
Let no. at ones place x+3
let no. ta tens place 10x
10x +30+x + 10x + x +3= 121
22x=88
x=88/22
x=4
the original no. is 74
the new no. is 47
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