solve the following equation 3x-2y+3=0,4x+3y-47=0 by. …
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Sia ? 6 years, 4 months ago
{tex}3x - 2y + 3 = 0{/tex}........(i)
{tex}4x + 3y - 47 = 0{/tex}......(ii)
By cross multiplication, we have
{tex}\therefore \frac { x } { [ ( - 2 ) \times ( - 47 ) - ( 3 \times 3 ) ] }{/tex}{tex}= \frac { y } { [ ( 3 \times 4 ) - ( - 47 ) \times 3 ] }{/tex}{tex}= \frac { 1 } { [ 3 \times 3 - ( - 2 ) \times 4 ] }{/tex}
{tex}\Rightarrow \quad \frac { x } { ( 94 - 9 ) } = \frac { y } { ( 12 + 141 ) } = \frac { 1 } { ( 9 + 8 ) }{/tex}
{tex}\Rightarrow \quad \frac { x } { 85 } = \frac { 1 } { 17 } , \frac { y } { 153 } = \frac { 1 } { 17 }{/tex}
{tex}17x = 85, \ 17y = 153{/tex}
{tex}\Rightarrow \quad x = \frac { 85 } { 17 } , y = \frac { 153 } { 17 }{/tex}
Therefore, the solution is {tex}x = 5,\ y = 9{/tex}
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