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İf x+y+z=12, and x²+y²+z²=64,then find xy+yz+zx.

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İf x+y+z=12, and x²+y²+z²=64,then find xy+yz+zx.

    • Posted by Grenvel Crasta 8 years, 2 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Amar Kumar 8 years, 2 months ago

    (x+y+z)2=x2+y2+z2+2xy+2yz+2zx

    122=64+2(xy+yz+zx)

    144-64=2(xy+yz+zx)

    80=2(xy+yz+zx)

    xy+yz+zx=40

     

     

     

    4Thank You

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