If p(x) is a polynomial of …

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Sia ? 6 years, 4 months ago
Let the polynomial be p(x).
By remainder theorem, p(2) = 1 and p(3) = 3.
p(x) can be expressed as q(x) × (x-2) × (x-3) + Ax + B, where Ax + B is the remainder when divided by (x -2) (x - 3). [Assuming p(x) as a cubic polynomial]
But p(2) = 1 and P(3) = 3,
2A + B = 1 and 3A + B = 3,
Solving the equations 2A + B = 1 and 3A + B = 3, we get A = 2 and B = -3
Hence the remainder when p(x) is divided by is (2x - 3).
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