Solve 3x-5y=4

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Sia ? 6 years, 4 months ago
Here given equations are

2x - y = 5 ..........(i)
3x - 5y = 4 ..............(ii)
Multiplying equation (i) by 3, we get
3 {tex}\times{/tex} (2x - y = 5)
{tex}\Rightarrow{/tex} 6x - 3y = 15 ...........(iii)
Multiplying equation (ii) by 2 , we get
2 {tex}\times{/tex} (3x - 5y = 4)
{tex}\Rightarrow{/tex} 6x - 10y = 8 ............(iv)
Subtracting equation (iv) from (iii), we get
{tex}\Rightarrow{/tex} y = 1
Put y = 1, equation (i) becomes
2x - 1 = 5
{tex}\Rightarrow{/tex} 2x = 6
{tex}\Rightarrow{/tex} x = 3
{tex}\therefore{/tex} x = 3, y = 1 is the solution of given system of equations.
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