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If the HCF of 210 and …

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If the HCF of 210 and 55 is expressible in the form 210 multiply 5 add 55 y , find y
  • 1 answers

Yogita Ingle 6 years, 8 months ago

Let us first find the HCF of 210 and 55.

Applying Euclid division lemna on 210 and 55, we get

210 = 55 × 3 + 45

55 = 45 × 1 + 10 

45 = 4 × 10 + 5 

10 = 5 × 2 + 0 

We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.

∴ 5 = 210 × 5 + 55y

⇒ 55y = 5 - 1050 = -1045

∴ y = -19

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