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Find HCF of 378 ,180 and …

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Find HCF of 378 ,180 and 420 by prime factorisation method .If hcf*LCM of three numbers equal to the product of the three nunbers

    • Posted by Vishnupriya Venkatraman 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 4 months ago

    The prime factors of:
    378 = 2 {tex} \times{/tex} 33 {tex}\times{/tex} 7
    180 = 23 {tex}\times{/tex} 32 {tex}\times{/tex} 5
    420 = 22 {tex}\times{/tex} 3 {tex}\times{/tex} 7{tex}\times{/tex} 5
    HCF = 2 {tex}\times{/tex} 3=6
    and LCM(378, 180, 420) = 22 {tex}\times{/tex} 33 {tex}\times{/tex} 5 {tex}\times{/tex} 7 = 3780
    HCF {tex}\times{/tex} LCM = 6 {tex}\times{/tex} 3780 = 22680
    Product of given numbers is = 378 {tex}\times{/tex} 180 {tex}\times{/tex} 420 = 28576800
    Hence, HCF {tex}\times{/tex} LCM {tex}\ne{/tex} Product of three numbers.

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