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Find the least no.which when divided …

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Find the least no.which when divided by 35,56 and 91 leaves the remainder 7 in each case

Posted by Hãrshîkä Váshkìyār 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

35 = 5 {tex}\times{/tex} 7
56 = 2³ {tex}\times{/tex} 7
91 = 13 {tex}\times{/tex} 7
L.C.M of 35, 56 and 91 = 2³ {tex}\times{/tex} 7 {tex}\times{/tex} 5 {tex}\times{/tex} 13 = 3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
Hence 3647 is the smallest number that, when divided by 35, 56 and 91 leaves a remainder of 7 in each case.

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