Zeros of quadratic polynomial f(x)=6x-3,verify relationship …
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Sia ? 5 years, 8 months ago
f(x)=6x2-3
To find zeros
6x2-3=0
6x2=3
x=±1√2
Henc the zeros f(x) are:
α=1√2 and β=−1√2
Sum of the zeroes = α+β=1√2+(−1√2)=0 and, − Coefficient of x Coefficient of x2=−06=0
∴ Sum of the zeros =− Coefficient of x coefficient of x2
Also, Product of the zeroes = αβ=1√2×−1√2=−12, and Constant term Coefficient of x2=−36=−12
∴ Product of the zeros = Constant term Coefficient of x2
0Thank You