Elimination by substitution :- 9x-3y=9 -------> [ 1 ] Equ. 3x - y = 3 ------> [ 2 ]Equ. 3x = 3 + y , x = [3 + y]/ 3 Put this value in equation [1 ], 9 × { [3 + y]/ 3 } - 3y = 9, [27+9 y ] / 3 - 3y = 9, 9 [ 3 + 1 y ] / 3 = 9, 3 [ 3 + 1 y ] = 9, 9 + 3y = 9, 3y = 9 - 9, 3y = 0, y = 0, x = y + 3 / 3 = 0 + 3 / 3 = 1 Hence , x = 1 , y = 0

1Thank You

Pk . 6 years, 8 months ago

Naman g to solve with substitution method we must have at least 2 equation, but here both equation are equivalent to each other .

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