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Find the smallest number which leaves …

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Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively.
  • 1 answers

Sia ? 6 years, 4 months ago

The LCM of 28 and 32
28 = 2× 2 × 7=22×7
32 = 2 × 2 × 2 × 2 × 2=25

LCM = 25 × 7 = 224

Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32

= LCM of 8 & 12 = 224 - 20 = 204

Therefore, 204 is smallest number which when divided by 28 and 32  leaves remainder  8 and 12 respectively.

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