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Prove that :- sin10°sin30°sin50°sin70° = 1/16

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Prove that :- sin10°sin30°sin50°sin70° = 1/16
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Kuldeepsa Bhati 8 years, 2 months ago

LHS sin10 sin30 sin50 sin70 Convert in cos by 90- angle From last Cos20 cos40 cos60 cos 80 cos60=1/2 1/2 (cos20 cos40 cos80) Divide by 2sin20 1/2 (2sin20cos20 cos40 cos80/2sin20) 1/2 (sin40cos40 cos80/2sin20) 1/2 (2sin40cos40 cos80/2*2sin20) 1/2 (sin80cos80/4sin20) 1/2 (2sin80cos80/2*4sin20) 1/2 (sin160/8sin20) Sin160=sin20 1/2 (sin20/8sin20) Sin20 cancel with sin20 1/2 (1/8) 1/16 RHS
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