If the HCF of 152 and …
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Sia ? 5 years, 9 months ago
On applying the Euclid’s division lemma to find HCF of 152, 272, we get
272=152×1+120
Here the remainder = 0.
Using Euclid’s division lemma to find the HCF of 152 and 120, we get
152=120×1+32
Again the remainder = 0.
Using division lemma to find the HCF of 120 and 32, we get
120=32×3+24
Similarly,
32=24×1+8
24=8×3+0
HCF of 272 and 152 is 8.
272×8 + 152x = H.C.F. of the numbers
⇒ 8=272×8+152x
⇒ 8−272×8=152x
⇒8(1−272)=152x
⇒x=−2168152=−27119
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