If the HCF of 152 and …
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Sia ? 6 years, 4 months ago
On applying the Euclid’s division lemma to find HCF of 152, 272, we get
{tex}272 = 152\times1 + 120{/tex}
Here the remainder = 0.
Using Euclid’s division lemma to find the HCF of 152 and 120, we get
{tex}152 = 120\times1 + 32{/tex}
Again the remainder = 0.
Using division lemma to find the HCF of 120 and 32, we get
{tex}120 = 32\times3 + 24{/tex}
Similarly,
{tex}32 = 24\times1 + 8{/tex}
{tex}24 = 8\times3 + 0{/tex}
HCF of 272 and 152 is 8.
272{tex}\times{/tex}8 + 152x = H.C.F. of the numbers
{tex}\Rightarrow {/tex} {tex}8 = 272\times8 + 152x{/tex}
{tex}\Rightarrow{/tex} {tex}8 - 272\times8 = 152x{/tex}
{tex}\Rightarrow 8(1- 272) = 152x{/tex}
{tex}\Rightarrow x = \frac { - 2168 } { 152 } = \frac { - 271 } { 19 }{/tex}
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