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Two charges q1 and q2 placed …

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Two charges q1 and q2 placed at a separation of force of 12N.If the separation is changed to d',the force becomes 3N. What's the value of d' in the terms of d?

    • Posted by Someone ?? 6 years, 5 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Someone ?? 6 years, 5 months ago

    Thnk u so much

    0Thank You

    Mahak Agrawal 5 years, 5 months ago

    here we have two charges Q1 and Q2 which is separated by a force of 12N With distance D according to coloumb law here we will get our equation 1st. Now when the Same charges separated by distanceD’ Then the force becomes 3N Again with the use of coloumb law Here we have our second equation. Putting both the equation in ratio we will get 3d=d’ and here is the Value ofd’ in term of d? Give reply how’s the explanation?

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