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Two liquid's x and y on …

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Two liquid's x and y on mixing form an ideal solution the vapour pressure of solution containing 2 mol of x and 1 mol of y is 550mmHg but when 4 mol of x and 1 mol of are mixed the vapour pressure of solution thus formed is 560mmHg what will be the vapour pressure of pure x and pure y
  • 1 answers

Gaurav Seth 6 years, 8 months ago

According to Dalton's law of partial pressures: ptotal=pX+pY where the partial pressures of each component of the solution is directly proportional to its mole fraction:pX=xX poX So, Two equation can be obtained utilising the above information: 34poX+14poY=550 −−−(i)and45poX+15poY=560 −−−(ii)Multiplying equation (i) by 4 and equation (ii) by 5, we'll get3poX+1poY=2200 −−−(iii)4poX+1poY=2800 −−−(iv)Subtracting (iii) from (iv), we'll getpoX=600 mm HgPuting it in equation (iii), we'll get(3×600)+1poY=2200poY=2200 −1800 =400 mm Hg

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