x/3 + y/4 =11 5x/6 - …
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Posted by Umtudokelombi Umtudokelombi 5 years, 10 months ago
- 1 answers
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Sia ? 5 years, 10 months ago
The given equations are
x3+y4=11
5x6−y3=−7
Now x3+y4=11
⇒4x+3y12=11 (by taking LCM)
4x+3y=132 ......(i)
5x6−y3=−7
5x−2y6=−7(by taking LCM)
5x−2y=−42.........(ii)
Multiplying (i) by 2 and (ii) by 3, we get
8x+6y=264 ........(iii)
15x−6y=−126 ........(iv)
Adding (iii) from (iv), we get
23x=138 ⇒ x=6
Substituting x = 6 in (i),we get
4×6+3y=132⇒3y=132−24
3y=108
y=36
∴ Solution is x=6,y=36
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