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x/3 + y/4 =11 5x/6 - …

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x/3 + y/4 =11 5x/6 - y/3=-7
  • 1 answers

Sia ? 5 years, 10 months ago

The given equations are
x3+y4=11
5x6y3=7
 Now x3+y4=11
 4x+3y12=11 (by taking LCM)
4x+3y=132 ......(i)
5x6y3=7
5x2y6=7(by taking LCM)
5x2y=42.........(ii)
Multiplying (i) by 2 and (ii) by 3, we get
8x+6y=264 ........(iii)
15x6y=126 ........(iv)
Adding (iii) from (iv), we get
23x=138  x=6
Substituting x = 6 in (i),we get
4×6+3y=1323y=13224
3y=108
y=36
 Solution is x=6,y=36

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