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The sum of the digits of …

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The sum of the digits of a two digit number is 8 and the difference between the number and that formed by reversing the digits is 18 find the number

    • Posted by Manohar Rg 6 years, 9 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Yogita Ingle 6 years, 9 months ago

    Let the unit place digit be x
    And tens place digit be y
    No. Formed by x and y = 10y+x (I have multiplied y by ten because it is on tens place)
    Now, no. Obtained by reversing digits = 10x+y
    Here sum of digits = 8 (I)
    And difference on reversing digits is 18
    A/q
    (10y+x) - (10x+y) = 18
    Or, 10y+x-10x-y= 18
    Or, 9y-9x = 18
    Or, 9(y-x) = 18
    Or y-x = 18/9= 2(ii)
    On adding both the given equation
    Now, y+x = 8
    y-x = 2
    ------------------
    2y. = 10
    Or, y =5
    Now putting the value of y in equation 1st
    y+x=8
    5+x=8
    Or, x= 3
    Now the formed no. = 53

     

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