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working of galvanometer

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working of galvanometer
  • 1 answers

Gaurav Seth 6 years, 11 months ago

Principle:

Its working is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque.

Working:

Suppose the coil <i>PQRS</i> is suspended freely in the magnetic field.

Let

<i>l</i> = Length <i>PQ</i> or <i>RS</i> of the coil

<i>b</i> = Breadth <i>QR</i> or <i>SP</i> of the coil

<i>n</i> = Number of turns in the coil

Area of each turn of the coil, <i>A</i> = <i>l</i> × <i>b</i>

Let <i>B</i> = Strength of the magnetic field in which coil is suspended

<i>I </i>= Current passing through the coil in the direction <i>PQRS</i>

Let, at any instant, α be the angle which the normal drawn on the plane of the coil makes with the direction of magnetic field.

The rectangular coil carrying current when placed in the magnetic field experiences a torque whose magnitude is given by,

τ = <i>nIBA</i> sin<i>α</i>

Due to deflecting torque, the coil rotates and suspension wire gets twisted. A restoring torque is set up in the suspension wire.

Let <i>θ</i>be the twist produced in the phosphor bronze strip due to rotation of the coil and <i>K</i> be the restoring torque per unit twist of the phosphor bronze strip. Then,

Total restoring torque produced =<i> k</i><i>θ</i>

In equilibrium position of the coil,

Deflecting torque = Restoring torque

∴ <i>NIBA = k</i><i>θ</i>

Or, 

Where, [constant for a galvanometer]

It is known as galvanometer constant.

  • Current sensitivity of the galvanometer is the deflection per unit current. 

  • Voltage sensitivity is the deflection per unit voltage.

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