Find the speed of the electron …
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Posted by Aatish Kumar 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
Let, electron of hydrogen atom at ground state n1=1
v1=e2/n14πε0(h/2π)= e2/2ε0h
where, e = 1.6 x 10-19C, ε0= 8.85 x 10-12 /NC2/m2, h = 6.62 x 10-34 Js
then,
v1=e2/2ε0h
= (1.6 x 10-19)2/ 2x2x8.85 x 10-12 x 6.62 x 10-34
= 1.09 x 106 m/s
for n3 = 3,
then,
v1=e2/ n32ε0h
= (1.6 x 10-19)2/ 3x2x8.85 x 10-12 x 6.62 x 10-34
= 7.27 x 106 m/s
3Thank You