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given triangle ABC is similar to …

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given triangle ABC is similar to triangle PQR, if AB/PQ= 1/3, then find ar(ABC)/ar(PQR)
  • 1 answers

Gaurav Seth 6 years, 9 months ago

ΔABC ~  ΔPQR

AB / PQ = BC / QR = AC / PR = 1 / 3

and    AB / PQ = BC / PQ = AC / PR = 1 / 3

ar ΔABC / ar ΔPQR = (1 / 3)2 = 1 / 9

ar ΔABC / ar ΔPQR  = 1 / 9

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