Find the coordinates of points on …

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Ram Kushwah 6 years, 9 months ago
Let the point on x axis is A (x,0) Let Bis (-11,8)
AB^2=(x+11)^2+(0-8)^2
172=x2+22x+121+64
x2+22x+185-172=0
x2+22x-104=0
x2+26x-4x-104=0
x(x+26)-4(x+26)=0
(x+26)(x-4)=0
x=-26 or 4
So Coordinates of the said two pints are
(-26,0) and (4,0)
0Thank You