Prove that 1upon root 2 is …

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Ram Kushwah 6 years, 9 months ago
We assume that 1/{tex}\sqrt2{/tex} is a rational no
So {tex}\frac ab=\frac{1}{\sqrt2}{/tex}
( Where and b are co-primes)
b=a{tex}\sqrt 2{/tex}
b2=2a2--------(1)
b2 is divisible by 2 ,so b is divisible by 2-----(2)
Let b=2c( c is any integer)
b2=4c2
2a2=4c2
a2=2c2
So a2 is divisible by 2,So a is divisible by 2-----(3)
From (2) and (3)
a and b are divisible by 2
But this contradict the assumption that a and b are co-prime ,So no common factor in and b except 1
Hence our assumption that 1/ {tex}\sqrt2{/tex} is wrong ,
Hence 1/{tex}\sqrt2{/tex} is a non prime number
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0Thank You