Calculate the no. of atoms of …
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Posted by Nikhil Malik 6 years, 11 months ago
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Payal Singh 6 years, 11 months ago
Molecular mass of Na2CO3 = ( 2 × 23 ) + 12 + (3 × 16) = 46 + 12 + 48 = 106
Given mass of Na2CO3 = 53 g
106 g of Na2CO3 Contain = 1 mol
53 g of Na2CO3 Contain = {tex}{53\over 106} = {1\over 2}{/tex} mol
No of atoms of Na = {tex}{1\over 2}\times 2 \times 6.022 \times 10^{23}{/tex}= {tex} 6.022 \times 10^{23}{/tex}
No of atoms of C = {tex}{1\over 2}\times 6.022 \times 10^{23}{/tex}
= {tex}3.011 \times 10^{23}{/tex}
No of atoms of O = {tex}{1\over 2}\times 3 \times 6.022 \times 10^{23}{/tex}= {tex}9.033\times 10^{23}{/tex}
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