Find the perimeter of an isosceles …

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Posted by Garima Joshi 8 years, 6 months ago
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Hans Raj 8 years, 6 months ago
let ABC a right ld triangle rt ld at B and side AB = BC=a
Area=1/2 x ABXBC = 1/2Xa2 = 200
a= root 400 = 20 cm
AC2 = a2+a2
= 400 + 400 = 800
AC=root 800 = 20root2
perimeter = AB+BC+AC = 20+20+20root2
= 20 x 2 root2 cm
= 20 x 2{tex} \sqrt2{/tex} cm
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