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If A+B =90 then prove that …

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If A+B =90 then prove that √tanA+tanB. cotB/sinA. secB -sin squareB/cos cubeA=tanA

Posted by Tashab Ali 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Gaurav Seth 6 years, 9 months ago

Given,LHS=√tanAtanB+tanAcotB/sinAsecB-sin²B/cos²B

=√tanAtan(90-A)+tanAcot(90-A)/sinAsec(90-A)-sin²(90-A)/cos²A

=√tanAcotA+tanAtanA/sinAcosecA-cos²A/cos²A

=√1+tan²A/1-1

=√tan²A

=tanA

1Thank You

Shivam Tripathi 6 years, 9 months ago

U r new tenthian maths he.........u

0Thank You

Heart ? Hacker 6 years, 9 months ago

Paper ho gya ab dimag kharab mat kar

0Thank You

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