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find the largest no which divides 615 and 963 leaving the remainder 6 in each case

Posted by Taj Ameena 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Yogita Ingle 6 years, 9 months ago

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.
Consider HCF be x.
In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.
609 = 3 x 3 x 29
957= 3 x 11 x 29
⇒ x = 3 x 29 = 87
∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

0Thank You

👉👉Tripti Pal👈👈 6 years, 9 months ago

Maths exam is over bro now next is hindi see the date sheet

0Thank You

Anushka Jugran ✌️ 6 years, 9 months ago

87...

0Thank You

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CBSE > Class 10 > Mathematics