The coefficient of 5th,6th,7th term are …
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Posted by Ishita Tomar 9 years, 1 month ago
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Naveen Sharma 9 years ago
In the expension of (1+X)n, T(r+1) = nCr Xr
Cofficient of (r+1)th term = nCr
So Cofficient of 5th, 6th and 7th term ll be nC4 nC5 nC6 respectivily
As it is given these terms are in AP
So, 2 * ( nC5 ) = nC4 + nC6
(2 * n! ) / { (n-5)! 5!} = (n! ) / { (n-4)! 4!} + (n! ) / { (n-6)! 6!}
i think you can proceed from here .
1Thank You