Conider the number 4n, where n …

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Sia ? 6 years, 4 months ago
We have 4n where n = 1, 2, 3, 4.......
if n = 1 then 4n = 41 = 4
if n = 2 then 4n = 42 = 16 and so on
If a number ends with zero then it is divisible by 5.
Here, 4 and 16 are not divisible by 5.
Therefore, 4n can never end with zero.
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